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i = 0 for item in iterable: print i, item i += 1

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for i, item in enumerate(iterable): print i, item

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>>> list(enumerate('abc')) [(0, 'a'), (1, 'b'), (2, 'c')] >>> list(enumerate('abc', 1)) [(1, 'a'), (2, 'b'), (3, 'c')] ×Öµä/¼¯ºÏ ½âÎö

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my_dict = {i: i * i for i in xrange(100)} my_set = {i * 15 for i in xrange(100)} # There is only a difference of ':' in both Ç¿ÖÆ¸¡µãÊý³ý·¨

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result = 1.0/2

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from __future__ import division result = 1/2 # print(result) # 0.5

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expr = "[1, 2, 3]" my_list = eval(expr)

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>>> foo = [1, 2, 3, 4] >>> dir(foo) ['__add__', '__class__', '__contains__', '__delattr__', '__delitem__', '__delslice__', ... , 'extend', 'index', 'insert', 'pop', 'remove', 'reverse', 'sort'] µ÷ÊԽű¾

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>>> a = [1,2,3,4] >>> a[::-1] [4, 3, 2, 1] # This creates a new reversed list. # If you want to reverse a list in place you can do: a.reverse()

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>>> foo = "yasoob" >>> foo[::-1] 'boosay' ÓÅÑŵشòÓ¡

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from pprint import pprint pprint(my_dict)

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